For a certain organ pipe , three successive resonance observed are `425 , 595 and 765 Hz`. Taking the speed of sound to be `340 ms^(-1)` , find the length of the pipe , in meter .

For a certain organ pipe , three successive resonance observed are `42

1.	For a certain organ pipe , three successive resonance observed are `425 , 595 and 765 Hz`. Taking the speed of sound to be `340 ms^(-1)` , find the length of the pipe , in meter .
Answer» Correct Answer - `1` Since frequencies are in odd number ratio , the pipe has to be a closed pipe. Ratio of `3` frequencies `= 425 : 595 : 765` `= 5 : 7 : 9` So fundamental frequency ` = f = (425)/(5) = 85 Hz` For fundamental frequency `l = (v)/( 4f) = ( 340)/(4 xx85) = 1m`

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For a certain organ pipe , three successive resonance observed are `425 , 595 and 765 Hz`. Taking the speed of sound to be `340 ms^(-1)` , find the length of the pipe , in meter .

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