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For a chemical reaction rate law is, rate `= k{A]^(2)[B]`. If [A] is doubled at constant [B], the rate of reactionA. increases by a factor of 8B. increases by a factor of 4C. incr-eases by a factor of 3D. increases by a factor of 2 |
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Answer» Correct Answer - B Given, Initial rate `= k [A]^(2) [B]` if `[A]^(1) = 2 [A]` Rate `k= [2A]^(2) [B] 4k [A]^(2) [B]` Thus, if the concenration of A, [A] is doubled and that of [B] is constant, then initial rate increases by a factor of 4. |
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