For a concentrated solution ofa weak electrolyte, A_(x) B_(y) of concentration 'C', the degree of dissociation alpha is given by

For a concentrated solution ofa weak electrolyte, A_(x) B_(y) of conce

1.	For a concentrated solution ofa weak electrolyte, A_(x) B_(y) of concentration 'C', the degree of dissociation alpha is given by
Answer» `alpha=sqrt(K_(eq)//C (x+y))` `alpha = sqrt(K_(eq)C//(XY))` `alpha = (K_(eq)//C^(x+y-1)x^(x)y^(y))^(1//(x+y))` Solution :`{:(,A_(x)B_(y),hArrxA^(y+),+YB^(x-)),("INITIAL",c,""0," "0),("At eqm.",c"("1-alpha")",xcalpha,ycalpha):}` `K_(eq)=((xcalpha)^(x)(ycalpha)^(y))/(c(1-alpha))~~((xcalpha)^(x)(ycalpha)^(y))/(c)` `""("Taking"1-alpha~~1)` `or" "K_(eq)=(x^(x)y^(y)c^(x+y)alpha^(x+y))/(c)=x^(x)y^(y)c^(x+y-1)alpha^(x+y)` `:.alpha=(K_(eq)//c^(x+y-1)x^(x)y^(y))^(1//(x+y))`