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For a conductor current equal to 4mA, Current carried by a particular brush in a 2-pole machine will be _____(a) 16mA(b) 8mA(c) 2mA(d) 10mAThis question was posed to me in an international level competition.My question comes from Wave Winding in portion Armature Windings of DC Machines

Answer»

The CORRECT answer is (b) 8mA

To explain I would say: Conductor current in a wave wounded machine is half of the Ia. So, Ia= 8mA. All positive and all negative BRUSHES are respectively connected in PARALLEL to feed the external CIRCUIT. Thus, IBRUSH = Ia /(P/2). Solving we get Brush current = 8mA.



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