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For a first order reactin, rate constant is given is `log k = 14 - (1.2 xx 10^(4))/(T)`, then what will be value of temperature if its half life period is `6.93 xx 10^(-3) min` ?A. `100 K`B. `1000 K`C. `720 K`D. `327 K` |
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Answer» Correct Answer - B `logk = 14 - (1.2 xx 10^(4))/(T)` …….(i) `logk = log A - (E_(a) )/(2.303RT)` `t_(1//2) = 6.93 xx 10^(-3) min` `k = (0.693)/(6.93 xx 10^(-3)) = 100` `log 100 = 14 - (1.2 xx 10^(4))/(T)` `rArr T = 1000K` |
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