For a given 4-pole machine, carrying armature current 56.82 A, with 846 conductors. The mean flux density in the air gap under the interpoles is 0.5 Wb/m^2 on full load and radial gap length is 0.3 cm. Ampere-turns required for an interpole is ____________(a) 3198(b) 2099(c) 4198(d) 6297I have been asked this question during an online interview.I need to ask this question from Commutation Process -1 topic in portion Commutation Process & Excitation Methods of DC Machines

For a given 4-pole machine, carrying armature current 56.82 A, with 84

1.	For a given 4-pole machine, carrying armature current 56.82 A, with 846 conductors. The mean flux density in the air gap under the interpoles is 0.5 Wb/m^2 on full load and radial gap length is 0.3 cm. Ampere-turns required for an interpole is ____________(a) 3198(b) 2099(c) 4198(d) 6297I have been asked this question during an online interview.I need to ask this question from Commutation Process -1 topic in portion Commutation Process & Excitation Methods of DC Machines
Answer» The correct ANSWER is (c) 4198 Easy explanation: Required ampere-TURNS are given by ATi = ATA (peak) +(Bi/µ0 )lgi . Substituting the ATi =[(56.82846)/ (224 )] +(0.5/4π10^-7 )* 0.3*10^-2 =4198. Turns can be found by DIVIDING with armature CURRENT.

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