For a given exothermic reaction, K_(p) and K_(p) are the equilibirum constants at temperature T_(1) and T_(2) respectively. Assuming that heat of reaction is constant in temperature range between T_(1) and T_(2), it is readily observed that

For a given exothermic reaction, K_(p) and K_(p) are the equilibirum c

1.	For a given exothermic reaction, K_(p) and K_(p) are the equilibirum constants at temperature T_(1) and T_(2) respectively. Assuming that heat of reaction is constant in temperature range between T_(1) and T_(2), it is readily observed that
Answer» `K_(p) gt K'_(p)` `K_(p) lt K'_(p)` `K_(p) = K'_(p)` `K_(p) = (1)/(K_(p))` Solution :In EXOTHERMIC reaction, on INCREASING temperature value of `K_(p)` decreases. `:.``K_(p) gt K'_(p)`(Assumuing `T_(1) lt T_(2)`).