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For a given material, the rigidity modulus is ((1)/(3))^(rd) of Young's modulus. Its Poisson's ratio is |
Answer» <html><body><p>0<br/>0.25<br/>0.<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a><br/>0.5</p>Solution :The relationship of Poission.s ratio, <a href="https://interviewquestions.tuteehub.com/tag/rigidity-623827" style="font-weight:bold;" target="_blank" title="Click to know more about RIGIDITY">RIGIDITY</a> and Young.s modulus is <br/> `eta = Y/(2(1 - sigma))sigma` - Poisson.s ratio <br/> Here, `"" eta1/3 y implies 3 eta = y` <br/> Substituting the value, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> `sigma = 0.5`</body></html> | |