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For a GP, if `S_(n)=(4^(n)-3^(n))/(3^(n))`, then `t_(2)`=….. .A. `1/9`B. `2/9`C. `7/9`D. `4/9` |
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Answer» Correct Answer - D We have,`S_(n)=(4^(n)-3^(n))/(3^(n))` For `n=1,S_(1)=t_(1)=(4-3)/3=1/3` For n=2,`S_(2)=t_(1)+t_(2)=(4^(2)-3^(2))/(3^(2))=7/9` `therforet_(2)=7/9-t_(1)=7/9-1/3=(7-3)/9=4/9` |
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