For a liquid, enthalpy of fusion is 1.435 kCal mol^(-1) and molar entropy change is 5.26 cal mol^(-1) K^(-1). The freezing point of liquid in celcius will be ________

For a liquid, enthalpy of fusion is 1.435 kCal mol^(-1) and molar entr

1.	For a liquid, enthalpy of fusion is 1.435 kCal mol^(-1) and molar entropy change is 5.26 cal mol^(-1) K^(-1). The freezing point of liquid in celcius will be ________
Answer» SOLUTION :Tmp `= (DELTA H "fusion")/(Delta S "fusion") = (1.435 xx 10^(3))/(5.26) = 272.81 K` `= 0^(@)C`