For a liquid, enthalpy of fusion is 1.435 xx 10^(3) cal mol^(-1) and molar entropy change is 5.26 cal mol^(-1). Calculate the melting point of the liquid.

For a liquid, enthalpy of fusion is 1.435 xx 10^(3) cal mol^(-1) and m

1.	For a liquid, enthalpy of fusion is 1.435 xx 10^(3) cal mol^(-1) and molar entropy change is 5.26 cal mol^(-1). Calculate the melting point of the liquid.
Answer» Solution :`Delta H_(f) = 1.435 xx 10^(3), Delta S= 5.26` `Delta S= (Delta H)/(T_(MP))` `rArr M.P. = (1.435 xx 10^(3))/(5.26) = 273 = 0^(@)C`