For a liquid the vapour pressure is given by log_(10) P = (-400)/(T) + 10 Vapour pressure of the liquid is 10^(x) mm Hg at 400K. The value of x will be _______

For a liquid the vapour pressure is given by log_(10) P = (-400)/(T) +

1.	For a liquid the vapour pressure is given by log_(10) P = (-400)/(T) + 10 Vapour pressure of the liquid is 10^(x) mm Hg at 400K. The value of x will be _______
Answer» <P> Solution :`log P = (-400)/(T) + 10` at 400K, log `P = (-400)/(400) + 10 = - 9 RARR P = 10^(-9)`