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| 1. |
For a MOD-12 counter, the FF has a = 60 ns The NAND gate has a of 25 n sec. The clock frequency is |
| Answer» For a proper working, the clock period should be equal to or greater than tpd = Mod 12 - 4FFs = 4 x 60 = 240 nsec. Total tpd = 240 + 25 = 265 nsec. = fc and fc = 3.774 MHz. | |