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For a normal eye, the cornea of eye provides a converging power of `40 D` and the least converging power of the eye lens behind the cornea is `20 D`. Using this information, the distance between the retina and the cornea eye lens can be estimated to beA. 5 cmB. 2.5 cmC. 1.67 cmD. 1.5 cm |
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Answer» Correct Answer - C Given, power `(P_(1)) = 40 D` and power `(P_(2))=20 D` We have, `P_("eq")=P_(1)+P_(2)=40+20=60 D` So, `" "(1)/(f_("eq"))=(1)/(f_(1))+(1)/(f_(2))` `rArr " " f_("eq")=(100)/(P_("eq"))=(100)/(60)` `= 1.67 cm` |
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