1.

For a npn BJT transistor is 1.64 x 10 H. C = 10 F; C = 4 x 10 F and DC current gain is 90. Find and ( = cut off frequency, C = capacitance, C = parasitic capacitance, = transconductance, = gain BW product)

Answer» ∴ fT = 90 x 1.64 x 108 = 1.47 x 1010 Hz gm = 2pfT(Cμ + Cp) = 2 x p x 1.47 x 1010 = (10-14 + 4 x 10-13) gm= 38 mμ.


Discussion

No Comment Found