For a particular reversible reaction at temperature T, DeltaH and DeltaS were found to be both +ve. If T_(e) is the temperature at equilibrium, the reaction would be spontaneous when

For a particular reversible reaction at temperature T, DeltaH and Delt

1.	For a particular reversible reaction at temperature T, DeltaH and DeltaS were found to be both +ve. If T_(e) is the temperature at equilibrium, the reaction would be spontaneous when
Answer» SOLUTION :`DeltaG = DeltaH -TDELTAS` At EQUILIBRIUM, `DeltaG =0` ` 0 = DeltaH -TDeltaS` or `T_(e)DeltaS = DeltaH` `T_(e) = (DeltaH)/(DeltaS)` SINCE it is an endothermic reaction, it is favoured by high temperature so that `T gt T_(e)`.