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For a planet having mass equal to the Earth but radius is one fourth of radius of the Earth, then escape velocity for this planet will be………… |
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Answer» 11.2 km/s Escape velocity of planet `= sqrt(2(4R)G) = 2sqrt(2Rg)` `=2xx 11.2 = 22.4 km//s` (Escape velocity of earth = 11.2 `km s^(-1)` |
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