1.

For a planet having mass equal to the Earth but radius is one fourth of radius of the Earth, then escape velocity for this planet will be…………

Answer»

11.2 km/s
22.4 km/s
3.6 km/s
44.8 km/s

Solution :RADIUS of earth = 4 Radius of planet
Escape velocity of planet `= sqrt(2(4R)G) = 2sqrt(2Rg)`
`=2xx 11.2 = 22.4 km//s`
(Escape velocity of earth = 11.2 `km s^(-1)`


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