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For a positive constant t, let α,β be the roots of the quadratic equation x2+t2x−2t=0. If the minimum value of 2∫−1[(x+1α2)(x+1β2)+1αβ]dx is √ab+c where a,b,c∈N, then the least possible value of (a+b+c) is |
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Answer» For a positive constant t, let α,β be the roots of the quadratic equation x2+t2x−2t=0. If the minimum value of 2∫−1[(x+1α2)(x+1β2)+1αβ]dx is √ab+c where a,b,c∈N, then the least possible value of (a+b+c) is |
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