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For a reaction ............ |
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Answer» <P> `t=0""360""0""0""0` `t=t 360-P" "P""P""P` `P_(t)=360-P+P+P+P` `=360+2P=760` `2P=400` `P=200` `t=2.303/(3.52xx10^(-3)) "LOG" 360/(360-200)` `t=2.303/(3.52xx10^(-3)) "log" 360/160` `=(2.303xx0.352)/(3.52xx10^(-3))=23.03` min |
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