1.

For a reaction, 2A + B → CThe rate law is, rate = k x [A]2 x [B]. If the rate constant of the reaction is 3.74 x 10-2M-2s-1, calculate the rate of the reaction when the concentrations of A, B and C are 0.108 M, 0.132 M and 0.124 M respectively.

Answer»

Given : 

Rate constant of the reaction = k = 3.74 x 10-2 M-2 s-1

[A] =0.108 M, 

[B] = 0.132M, 

[C] = 0.124 M 

Rate of the reaction = R = ?

By rate law,

R = k [A]2 x [B] 

= (0.108)2 x 0.132 

= 1.54 x 10 Ms-1

(Concentration of C need not be considered since it is a product.)

∴ Rate of reaction = 1.54 x 10-3 Ms-1



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