InterviewSolution
Saved Bookmarks
| 1. |
For a reaction, 2A + B → CThe rate law is, rate = k x [A]2 x [B]. If the rate constant of the reaction is 3.74 x 10-2M-2s-1, calculate the rate of the reaction when the concentrations of A, B and C are 0.108 M, 0.132 M and 0.124 M respectively. |
|
Answer» Given : Rate constant of the reaction = k = 3.74 x 10-2 M-2 s-1 [A] =0.108 M, [B] = 0.132M, [C] = 0.124 M Rate of the reaction = R = ? By rate law, R = k [A]2 x [B] = (0.108)2 x 0.132 = 1.54 x 10 Ms-1 (Concentration of C need not be considered since it is a product.) ∴ Rate of reaction = 1.54 x 10-3 Ms-1 |
|