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The rate constant of a first order reaction is given by :(a) k = 2.303 \(\times\) t \(\times\) \(log_{10}\frac{a}{(a-x)}\) (b) \(\frac{k}{t}\) = 2.303 \(log_{10}\frac{a}{(a-x)}\) (c) k = \(\frac{2.303}{t}\)\(log_{10}\frac{1}{(a-x)}\) (d) k = \(\frac{2.303}{t}\)\(log_{10}\frac{a}{(a-x)}\) |
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Answer» Option : (d) k = \(\frac{2.303}{t}\)\(log_{10}\frac{a}{(a-x)}\) |
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