Saved Bookmarks
| 1. |
For a reaction A + B rarr C + D, the entropy change is +68.4 JK^(-1) and the enthalpy change is -124.6 kJ. Calculate the Gibb's energy change at 298 K. |
|
Answer» Solution :`Delta G = Delta H - T Delta S` Given, `Delta H = -1246000 J, T = 298 K` and `Delta S = +68.4 JK^(-1)` Substituting in the formula, we get `Delta G = -124600 - 298 xx 68.4` `= -144983 J = -144.983 KJ`. |
|