1.

For a reaction A + B rarr C + D, the entropy change is +68.4 JK^(-1) and the enthalpy change is -124.6 kJ. Calculate the Gibb's energy change at 298 K.

Answer»

Solution :`Delta G = Delta H - T Delta S`
Given, `Delta H = -1246000 J, T = 298 K` and `Delta S = +68.4 JK^(-1)`
Substituting in the formula, we get
`Delta G = -124600 - 298 xx 68.4`
`= -144983 J = -144.983 KJ`.


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