For a reaction `A(s)+2B^(o+) rarr A^(2+)+2B` `K_(c)` has been found to be `10^(12)`. The `E^(c-)._(cell)` isA. `0.354V`B. `0.708V`C. `0.0098V`D. `1.36V`

For a reaction `A(s)+2B^(o+) rarr A^(2+)+2B` `K_(c)` has been found to

1.	For a reaction `A(s)+2B^(o+) rarr A^(2+)+2B` `K_(c)` has been found to be `10^(12)`. The `E^(c-)._(cell)` isA. `0.354V`B. `0.708V`C. `0.0098V`D. `1.36V`
Answer» Correct Answer - a `E=E^(c-)-(0.059)/(2) log K` At equilibrium, `E=0` `E^(c-)=(0.059)/(2) log K =(0.059)/(2) log 10^(12)` `=(0.059)/(2)xx12=0.354`

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For a reaction `A(s)+2B^(o+) rarr A^(2+)+2B` `K_(c)` has been found to be `10^(12)`. The `E^(c-)._(cell)` isA. `0.354V`B. `0.708V`C. `0.0098V`D. `1.36V`

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