1.

For a reaction `DeltaH=(+3kJ), DeltaS=(+10J//K)` beyond which temperature this reaction will be spontaneousA. 300 KB. 200 KC. 273 KD. 373 K

Answer» Correct Answer - D
`DeltaG=DeltaH-TDeltaS`.
For the spontaneous reaction the `DeltaG` must be negative.
`DeltaH=3kJ=+3000 J`
`DeltaS=+10 J//K`
If `T=300 K implies DeltaG=3000-300xx10=0`
If `T=200 K implies DeltaG=3000-200xx10=1000 J`
If `T=273 K implies DeltaG=3000-273xx10=270 J`
If T = 373 K
`DeltaG=3000-373xx10=-730 J`
Hence, beyond 373 temperature the reaction will be spontaneous.


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