InterviewSolution
Saved Bookmarks
| 1. |
For a reaction `DeltaH=(+3kJ), DeltaS=(+10J//K)` beyond which temperature this reaction will be spontaneousA. 300 KB. 200 KC. 273 KD. 373 K |
|
Answer» Correct Answer - D `DeltaG=DeltaH-TDeltaS`. For the spontaneous reaction the `DeltaG` must be negative. `DeltaH=3kJ=+3000 J` `DeltaS=+10 J//K` If `T=300 K implies DeltaG=3000-300xx10=0` If `T=200 K implies DeltaG=3000-200xx10=1000 J` If `T=273 K implies DeltaG=3000-273xx10=270 J` If T = 373 K `DeltaG=3000-373xx10=-730 J` Hence, beyond 373 temperature the reaction will be spontaneous. |
|