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For a reaction x +y + z → products, the rate law is given by rate = k [x]3/2 [y]1/2 what is the overall order of the reaction and what is the order of the reaction with respect to z. |
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Answer» Rate = k [x]3/2[y]1/2 overall order = \(\Big(\frac{3}{2}+\frac{1}{2}\Big)\) = 2 i.e., second order reaction. Since the rate expression does not contain the concentration of Z , the reaction is zero order with respect to Z. |
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