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For a real number x, let [x] denote the largest integer less than or equal to x, and let {x}=x–[x]. The number of solutions x to the equation [x]{x}=5 with 0≤x≤2015 is |
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Answer» For a real number x, let [x] denote the largest integer less than or equal to x, and let {x}=x–[x]. The number of solutions x to the equation [x]{x}=5 with 0≤x≤2015 is |
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