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For a reversible reaction : `X_((g))+3Y_((g))iff2Z_((g)), DeltaH=-40kJ` the standard entropies of X, Y and Z are 60, 40 and 50 `JK^(-1) mol^(-1)` respectively. The temperature at which the above reaction attains equilibrium is aboutA. 400 KB. 500 KC. 273 KD. 373 K |
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Answer» Correct Answer - B `X_((g))+3Y_((g))iff2Z_((g))` `DeltaS^(@)=2S^(@)(Z)-{S^(@)(X)+3S^(@)(Y)}` `=2xx50-{60+3xx40}=100-180 " = - 80 J K"^(-1) mol^(-1)` `DeltaH^(@)=-40 kJ=-40,000 J," " DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)` At equilibrium, `DeltaG^(@)=0 " "therefore DeltaH^(@)=TDeltaS^(@)` `or, T = (DeltaH^(@))/(DeltaS^(@))=(40000)/(80)=500 K`. |
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