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For a reversible reactionn at 298 K the equilibrium constant K is 200. What is value of `DeltaG^(@)` at 298 K ?A. `-13.13kcal`B. `-0.13kcal`C. `-3.158kcal`D. `-0.413kcal` |
Answer» Correct Answer - C Applying `DeltaG^(@)=-2.303RTxxlogK` `" "=-2.303xx2xx298xxlog200` `" "=-3158.4" cal "=-3.158" kcal"` |
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