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| 1. |
For a satellite escape velocity is 11.2 km/s from the earth. If the satellite is launched at an angle of 60° with vertical, then find the escape speed. |
| Answer» Solution :`IMPLIES` Escape SPEED `V_e=sqrt((2G)/R_e)`, does not DEPEND on the ANGLE of projection and hence escape velocity is unchanged so it is 11.2 m/s. | |