1.

For a satellite escape velocity is 11.2 km/s from the earth. If the satellite is launched at an angle of 60° with vertical, then find the escape speed.

Answer»

Solution :`IMPLIES` Escape SPEED `V_e=sqrt((2G)/R_e)`, does not DEPEND on the ANGLE of projection and hence escape velocity is unchanged so it is 11.2 m/s.


Discussion

No Comment Found