1.

For a satellite moving in an orbit around the earth, the ratio of kinetic energy of potential

Answer»

2
`sqrt2`
`1/2`
`(1)/(sqrt2)`

Solution :`(GMm)/(R^2) = m omega^2 R`
`KE = 1/2 I omega^2= 1/2 mR^2 omega^2 = (GMm)/(2R)`
`PE= - (GMm)/(R )`
`(KE)/(|P.E|) = (GMm)/(2R) XX (R )/(GMm) = 1/2 `


Discussion

No Comment Found