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For a satellite moving in an orbit around the earth, the ratio of kinetic energy of potential |
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Answer» Solution :`(GMm)/(R^2) = m omega^2 R` `KE = 1/2 I omega^2= 1/2 mR^2 omega^2 = (GMm)/(2R)` `PE= - (GMm)/(R )` `(KE)/(|P.E|) = (GMm)/(2R) XX (R )/(GMm) = 1/2 ` |
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