InterviewSolution
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InterviewSolution
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For a single slit of width "a", the first minimum of the interference pattern of a monochromatic light of wavelength lambda occurs at an angle of (lambda)/(a). At the same angle of (lambda)/(a), we get a maximum for two narrow slits separated by a distance "a" . Explain. |
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Answer» Solution :In the first case, the OVERLAPPING of the contributions of the wavelets from TWO halves of a SINGLE slit produces a minimum because CORRESPONDING wavelets from two halves have path difference of `(lambda)/(2)`. In the second case, the OVERLAPING of the wave fronts from the two slits produces first maximum because these wave fronts have the path differences of `lambda`. |
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