For a transistor ampliflier in common emiter configuration for load imperdance of `1 k Omega (h_(fe) = 50 and h_(oe) = 25)` the current gain isA. `-5.2`B. `-15.7`C. `-24.8`D. `-48.78`

For a transistor ampliflier in common emiter configuration for load im

1.	For a transistor ampliflier in common emiter configuration for load imperdance of `1 k Omega (h_(fe) = 50 and h_(oe) = 25)` the current gain isA. `-5.2`B. `-15.7`C. `-24.8`D. `-48.78`
Answer» Correct Answer - D In common emitter configuration current gain `A_(1)=(-h_(fe))/(1+h_(oe)R_(L))=(-50)/(1+25xx10^(-6)xx10^(3))=-48.78`.

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For a transistor ampliflier in common emiter configuration for load imperdance of `1 k Omega (h_(fe) = 50 and h_(oe) = 25)` the current gain isA. `-5.2`B. `-15.7`C. `-24.8`D. `-48.78`

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