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For a transistor `beta = 40` and `I_(B) = 25 muA`. Find the value of `I_(E)`.A. 1mAB. `1.025 mA`C. 2 mAD. `1.2 mA` |
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Answer» Correct Answer - B `beta =(I_(C))/(I_(B))rArr I_(C) =beta I_(B) = 40 xx 25 xx 10^(-6) and I_(E)=I_(B) +I_(C)`. |
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