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For a transistor `x=(1)/(alpha)&y=(1)/(beta)` where `alpha & beta` are current gains in common base and common emitter configuration. ThenA. `x+y =1`B. `x -y =1`C. `2x =1 - y`D. `x+y =0` |
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Answer» Correct Answer - B `alpha -(Delta I_(c))/(Delta I_(e)), beta =(Delta I_(c))/(Delta I_(b))`. |
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