For a wave described by y = 0.5 sin(x - 60t) cm, find (i) amplitude (ii) wave-vector (iii) wavelength (iv) angular frequency and frequency (v) periodic time (vi) speed of wave.

For a wave described by y = 0.5 sin(x - 60t) cm, find (i) amplitude (i

1.	For a wave described by y = 0.5 sin(x - 60t) cm, find (i) amplitude (ii) wave-vector (iii) wavelength (iv) angular frequency and frequency (v) periodic time (vi) speed of wave.
Answer» Solution :Comparing `y =0.5 sin (x-60t)` with `y = 0.5 sin (kx - omega t )` (i) amplitude of a wave `A =0.5 cm` (II) wave vector K =1 rad/cm (iii) wavelength `LAMDA = (2pi)/(k) = (2XX 3.14)/(1) = 6.28 cm` (iv) anguylar frequency `omega = 2pi f = 60` rad/s `therefore` Frequency `f = (60)/(2pi) = (60)/(2 xx 3.14)= 9.554 Hz` (v) PERIODIC time `T = (1)/(f) = (1)/(9.554) = 0.1047 s ` (vi) wave speed `v = (omeg )/(k) = (60)/(1) = 60 (cm)/(s)`