InterviewSolution
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InterviewSolution
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For an aqueous solution freezing point is `-0.186^(@)C`. The boiling point of the same solution is `(K_(f) = 1.86^(@)mol^(-1)kg)` and `(K_(b) = 0.512 mol^(-1) kg)`A. 0.186B. 0.512C. 0.512//1.86D. 0.0512 |
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Answer» Correct Answer - D `Delta T_(b) = K_(b) xx "molality"` `Delta T_(b) = K_(b) xx"molality" ` `(Delta T_(b))/(Delta T_(f))=K_(b)/K_(f) ` or `Delta T_(b) = (Delta T_(f) xx K_(b))/K_(f)` `=(0.186 xx 0.512)/1.86=0.0512` |
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