For an e in a hydrogen atom, the wave function Psi is proportional toe^(-r//a_0) where a_0 as Bohr.s radius, what is the ratio of probability of finding the e^(-) at the nucleus to the probability of finding it at a_0, the wave function is Psi = 1/(sqrt(pi)) ((1)/(a_0))^(3/2) e^(-r//a_0)

For an e in a hydrogen atom, the wave function Psi is proportional toe

1.	For an e in a hydrogen atom, the wave function Psi is proportional toe^(-r//a_0) where a_0 as Bohr.s radius, what is the ratio of probability of finding the e^(-) at the nucleus to the probability of finding it at a_0, the wave function is Psi = 1/(sqrt(pi)) ((1)/(a_0))^(3/2) e^(-r//a_0)
Answer» e `e^2` `1//e^2` Zero Solution :HINTS: `Psi^2 = 1/(pi) ((1)/(a_0))^3 e^((-2r)/(a_0)) ` At nucleus `R=0` and in `1^(st)` orbit `r= a_0` `Psi^2 = 1/(pi) (1/(a_0))^3 e^(-3) , (Psi_n^2)/(Psi_0^2) = e^2`