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For an equilibrium reaction, `N_(2)O_(4)(g) hArr 2NO_(2)(g)`, the concentrations of `N_(2)O_(4)` and `NO_(2)` at equilibrium are `4.8 xx 10^(-2)` and `1.2 xx 10^(-2) mol//L` respectively. The value of `K_(c)` for the reaction isA. `3xx 10^(-1) " mol " L^(-1)`B. `3xx 10^(-3) " mol "L^(-1)`C. `3xx10^(3) " mol " L^(-1)`D. `3.3 xx 10^(3) " mol " L^(-1)` |
Answer» Correct Answer - B `K_(c) =((1.2 xx 10^(-2) "mol "L^(-1))^(2))/((4.8 xx 10^(-2) " mol "L^(-1))) =3.0 xx 10^(-3) "mol "L^(-1)` |
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