1.

For an equilibrium reaction, the rate constants for the forward and the backward reaction are 2.38 xx 10^(-4) and 8.15 xx 10^(-5)respectively . Calculate the equilibrium constant for the reaction.

Answer»

Solution :Equilibrium CONSTANT `K= (k_(f))/(k_(b)) = (2.38 xx10^(-4))/(8.15 XX 10^(-5))=2.92`


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