For an ideal gas a process PV diagram is a circle. An adiabatic from A passes through C. An isothrem from A passes through B. We take a part of the circular cyclic process. Comment on the sign of the quantity of column -I {:("Column"-I,"Column"-II),((A)"Heat given to the gas in going from A to C along circle",(P)"Positve"),((B)"Heat given to the gas in going from B to C along circle",(Q)"Negative"),((C)"Heat given to the gas in going from C to D along circle",(R)"Zero"),(,(S)"can't be said"):}

For an ideal gas a process PV diagram is a circle. An adiabatic from A

1.	For an ideal gas a process PV diagram is a circle. An adiabatic from A passes through C. An isothrem from A passes through B. We take a part of the circular cyclic process. Comment on the sign of the quantity of column -I {:("Column"-I,"Column"-II),((A)"Heat given to the gas in going from A to C along circle",(P)"Positve"),((B)"Heat given to the gas in going from B to C along circle",(Q)"Negative"),((C)"Heat given to the gas in going from C to D along circle",(R)"Zero"),(,(S)"can't be said"):}
Answer» SOLUTION :(A)A to C along circe net work DONE is + ve and triangleV is - ve But `(triangle omega - triangleV) gt` 0 So, `TRIANGLEQ = triangle omega - triangle U` `triangleQ gt 0` (B)Bto CALONG circle there is compression so work done is (-ve) and `triangleU is (-ve) so triangleQ is -ve` (c) Same as B to C along circle