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For an ideal gas isobaric process at pressure 1 Pa, the volume of the gas changes from 1 m^3 to 5 m^3, what is the work done by the gas?(a) 1 J(b) 4 J(c) 5 J(d) 10 J |
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Answer» Correct answer is (b) 4 J The explanation is: W = P∆V = 1*(5 – 1) = 4 J. |
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