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For an ideal gas isobaric process what is the work done by the gas from 2 m^3 to 0.5 m^3 at 2 Pa?(a) -3 J(b) 3 J(c) -5 J(d) 5 J |
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Answer» The correct answer is (a) -3 J For explanation: Work done by the gas = 2*(0.5 – 2) = -3 J. |
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