For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using the expression w = "-nRT" In (V_(f))/(V_(i)) A sample containing 1.0 mol of an ideal gas is expanded isothermally and reveribly to ten times of its original volume, in two separate experimentsThe expansion is carried out at 300 K and at 600 K respectively.Choose the correct option

For an ideal gas, the work of reversible expansion under isothermal co

1.	For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using the expression w = "-nRT" In (V_(f))/(V_(i)) A sample containing 1.0 mol of an ideal gas is expanded isothermally and reveribly to ten times of its original volume, in two separate experimentsThe expansion is carried out at 300 K and at 600 K respectively.Choose the correct option
Answer» Work done at 600K is 20 times the work done at 300 K Work done at 300 K is TWICE the work done at 600 K Work done at 600 K is twice the work done at 300 K `DeltaU = 0` in both CASES Solution :`w = -nRT In (V_(f))/(V_(i))`.Here, N, R and In`(V_(f))/(V_(i))` are same in both the cases, therefore, `(w_(2))/(w_(1)) = (T_(2))/(T_(1))` or `(w(600 K))/(w(300 K)) = (600 K)/(300 K) = 2` i.e. Work done at 600 K is twice the work done at 300K.Since each case involves isothermal expansion of an ideal gas, there is no change in internal energy i.e. `DeltaU = 0`.