For angle of projection of a projectile at angles and (45^(@)+theta), the horizontal range described by the projectile are in the ratio of

For angle of projection of a projectile at angles and (45^(@)+theta),

1.	For angle of projection of a projectile at angles and (45^(@)+theta), the horizontal range described by the projectile are in the ratio of
Answer» `2:1` `1:1` `2:3` `1:2` SOLUTION :Horizontal RANGE, `R=(U^(2)sin 2theta)/(G)` For angle ofprojection `(45^(@)-theta)`.the horizontal range is `R_(1)=(u^(2)sin [2(45^(@)-theta)])/(g)=(u^(2)sin(90^(@)-2theta))/(g)=(u^(2)cos 2 theta)/(g)` `:.(R_(1))/(R_(2))=(u^(2)cos 2 theta//g)/(u^(2)cos 2 theta//g)=(1)/(1)`