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For any integer m>=3, the series 2+4+6+…+(4m) can be equivalent to |
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Answer» to FIND the sum of ..2+4+6+...+4mExplanation:first 2 can be taken common from the given SEQUENCE2(1+2+3+...+2m)then it becomes..2(2m)(2m+1)/2..two will be removed..therefore it becomes..2m(2m+1) ..minimum value of this SEQUENCE is2×3(2×3+1)=42 it's minimum value at m=3HOPE THIS HELPS YOU.. |
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