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For any θ∈(π4,π2), the expression 3(sinθ−cosθ)4+6(sinθ+cosθ)2+4sin6θ equals: |
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Answer» For any θ∈(π4,π2), the expression 3(sinθ−cosθ)4+6(sinθ+cosθ)2+4sin6θ equals: |
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