For are reaction at 298 K is K_p=1.7xx10^12, So "J mol"^(-1) a find DeltaG^ө.(R=8.314 J mol^(-1) K^(-1) )

For are reaction at 298 K is K_p=1.7xx10^12, So "J mol"^(-1) a find De

1.	For are reaction at 298 K is K_p=1.7xx10^12, So "J mol"^(-1) a find DeltaG^ө.(R=8.314 J mol^(-1) K^(-1) )
Answer» SOLUTION :`DeltaG^ө=-6.9785xx10^4 "J MOL"^(-1) = -69.78 "KJ mol"^(-1)`