InterviewSolution
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InterviewSolution
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For balmer series wavelength of first line is `lambda_(1)` and for brackett series wavelength of first line is `lambda_(2)` then `(lambda_(1))/(lambda_(2))` isA. 0.81B. 0.162C. 0.198D. 0.238 |
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Answer» Correct Answer - c For balmer series wavelength of first line `(lambda_(1))` is give by `(1)/(lambda_(1))=R(1)/(2^(12)-(1)/(3^(2))=(5R)/(36)` where R is Rydberg constant For brackett series wavelength of first line `(lambda_(2))` is given by `(1)/(lambda_(2))=R(1)/(4^(2)-(1)/(5^(2))=(9R)/(400)` `therefore (lambda_(1))/(lambda_(2))=(1//lambda_(2))/(1//lambda_(1))=(9R // 400)/(5R // 36)=0.162` |
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