For cationic hydrolysis, pH given by

1.	For cationic hydrolysis, pH given by
Answer» `PH=(1)/(2)pK_(w)+(1)/(2)pK_(a)+(1)/(2)log C` `pH=(1)/(2)pK_(w)-(1)/(2)pK_(a)-(1)/(2)log C` `pH=(1)/(2)pK_(w)+(1)/(2)pK_(a)-(1)/(2)pK_(b)` `pH=(1)/(2)pK_(w)+(1)/(2)pK_(b)+(1)/(2)log C` Solution :`B^(+)+H_(2)O hArr BOH+H^(+)` `[H^(+)] = ((K_(w).C)/(K_(b)))^(1//2)` `pH= - log[H^(+)]= -"log" ((K_(w).C)/(K_(b)))^(1//2)` `= (-1)/(2)[log K_(w)-logK_(b)+log C]` `= (1)/(2)[pK_(w)-pK_(b)-logC]`

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