InterviewSolution
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InterviewSolution
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For cationic hydrolysis, pH given byA. `pH=(1)/(2)pK_(w)+(1)/(2)pK_(a)+(1)/(2)log C`B. `pH=(1)/(2)pK_(w)-(1)/(2)pK_(a)-(1)/(2)log C`C. `pH=(1)/(2)pK_(w)+(1)/(2)pK_(a)-(1)/(2)pK_(b)`D. `pH=(1)/(2)pK_(w)+(1)/(2)pK_(b)+(1)/(2)log C` |
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Answer» Correct Answer - B `B^(+)+H_(2)O hArr BOH+H^(+)` `[H^(+)] = ((K_(w).C)/(K_(b)))^(1//2)` `pH= - log[H^(+)]= -"log" ((K_(w).C)/(K_(b)))^(1//2)` `= (-1)/(2)[log K_(w)-logK_(b)+log C]` `= (1)/(2)[pK_(w)-pK_(b)-logC]` |
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